RtreeType of regular tree with nodes labelled by values of type 'a The implementation uses de Bruijn indices, so binding capture is avoided by the lift operator (see example below)
Building trees
val mk_rec_calls : int -> 'a t arrayBuild mutually recursive trees: X_1 = f_1(X_1,..,X_n) ... X_n = f_n(X_1,..,X_n) is obtained by the following pseudo-code let vx = mk_rec_calls n in let |x_1;..;x_n| = mk_rec|f_1(vx.(0),..,vx.(n-1);..;f_n(vx.(0),..,vx.(n-1))|
First example: build rec X = a(X,Y) and Y = b(X,Y,Y) let |vx;vy| = mk_rec_calls 2 in let |x;y| = mk_rec |mk_node a [|vx;vy|]; mk_node b [|vx;vy;vy|]|
Another example: nested recursive trees rec Y = b(rec X = a(X,Y),Y,Y) let |vy| = mk_rec_calls 1 in let |vx| = mk_rec_calls 1 in let |x| = mk_rec|mk_node a vx;lift 1 vy| let |y| = mk_rec|mk_node b x;vy;vy| (note the lift to avoid
lift k t increases of k the free parameters of t. Needed to avoid captures when a tree appears under mk_rec
val is_node : 'a t -> boolval dest_param : 'a t -> int * intdest_param is not needed for closed trees (i.e. with no free variable)
val is_infinite : ('a -> 'a -> bool) -> 'a t -> boolTells if a tree has an infinite branch. The first arg is a comparison used to detect already seen elements, hence loops
Rtree.equiv eq eqlab t1 t2 compares t1 t2 (top-down). If t1 and t2 are both nodes, eqlab is called on their labels, in case of success deeper nodes are examined. In case of loop (detected via structural equality parametrized by eq), then the comparison is successful.
Rtree.equal eq t1 t2 compares t1 and t2, first via physical equality, then by structural equality (using eq on elements), then by logical equivalence Rtree.equiv eq eq
Iterators
module Smart : sig ... end